16-3.Concentrated load of support beams at both ends
16-3.Concentrated load of support beams at both ends
Symbol description and unit
Maximum deflectionF(mm)
ƒÂmax=1/(9*3
0.5
)*W*L
2
*(L
2
-L
2
2
)
1.5
/(E*I*L)
ƒÂmax=
Maximum deflection angleF( Every time)
‚h max(x=0)=1/6 *W*L
2
*(L
2
-L
2
2
)*180/(E*I*L*ƒÎ)
‚hmax(x=0)=
‚hmax(x=L)=1/6 *W*L
1
*(L
2
-L
1
2
)*180/(E*I*L*ƒÎ)
‚hmax(x=L)=
Maximum stressF(Kg/mm
2
)
ƒÐmax=Mmax/Z=W*L
1
*L
2
/(L*Z)
ƒÐmax=
EFYoung's modulus (Kg/mm
2
)
Steel:21000
Stainless steel:19000
Aluminum:7000A cast iron:10000
IFMoment of inertia of area (mm
4
)
ZFMoment of inertia (mm
3
)
‚vF Load B (Kg)
LF Beam length (mm)
L
1
F Beam length to load position (mm)
L
2
FBeam length to load position (mm)
Reference: "Machine Design Handbook for Engineers" (Revised version by Saburo Kano) Applied Structural Mechanics Beam Calculation Table, page 141, refer to beams and columns.